How do you divide $(3r^3+11r^2-6r-18)div(r+4)$ using synthetic division?

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Answer 1 · 2018-02-13T08:45:24

$3r^2-r-2-10/(r+4)$

$(3r^3+11r^2-6r-18)/(r+4)$

....... 3 .... 11 .... -6 ..... -18
-4 | $darr$ .. -12 ...... 4 ......... 8
....... 3 ..... -1 ..... -2 .... -10 => Remainder

$=3r^2-r-2-10/(r+4)$

How do you divide (3r^3+11r^2-6r-18)div(r+4)(3r^3+11r^2-6r-18)div(r+4) using synthetic division?