How do you divide $(3x^3 + 17x^2 + 15x + 2)$ by $x+5$ ?

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Answer 1 · 2018-03-20T01:19:49

$3x^2+2x+5-(8)/(x+5)$

General process: multiply $x+5$ by a quantity that allows you to match the largest power of $x$ term in the quantity inside.

So the first step, you would do $(x+5)xx3x^2$ in order to produce the term $3x^3$ .

Similarly, in the second step you do $(x+5)xx2x$ to match $2x^2$ .

The third step you do $(x+5)xx5$ to produce $5x$ .

Since $-8$ is an $x^0$ term, this is less than the $x^1$ term in $x+5$ . So this where we stop. $-8$ becomes the remainder.

I have colored various quantities to show how the answer is put together after the division.

I apologize for the trackpad handwriting.

How do you divide (3x^3 + 17x^2 + 15x + 2) (3x^3 + 17x^2 + 15x + 2) by x+5x+5?