How do you divide $\frac{3 x^{3} - 5 x^{2} + 10 x + 4}{3 x + 1}$ $( 3x^3 - 5x^2 + 10x +4 )/(3x+1)$ ?

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How do you divide $\frac{3 x^{3} - 5 x^{2} + 10 x + 4}{3 x + 1}$ $( 3x^3 - 5x^2 + 10x +4 )/(3x+1)$ ?

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Answer 1 · 2016-11-04T16:21:37

The answer is $= x^{2} - 2 x + 4$ $=x^2-2x+4$

Explanation:

Let's do the long division
$a a a$ $color(white)(aaa)$ $3 x^{3} - 5 x^{2} + 10 x + 4$ $3x^3-5x^2+10x+4$ $a a a$ $color(white)(aaa)$ $∣$ $∣$ $3 x + 1$ $3x+1$
$a a a$ $color(white)(aaa)$ $3 x^{3} + x^{2}$ $3x^3+x^2$ $a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $∣$ $∣$ $x^{2} - 2 x + 4$ $x^2-2x+4$
$a a a a$ $color(white)(aaaa)$ $0 - 6 x^{2} + 10 x$ $0-6x^2+10x$
$a a a a a a a$ $color(white)(aaaaaaa)$ $- 6 x^{2} - 2 x$ $-6x^2-2x$
$a a a a a a a a a a$ $color(white)(aaaaaaaaaa)$ $0 + 12 x + 4$ $0+12x+4$
$a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaa)$ $+ 12 x + 4$ $+12x+4$
$a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaa)$ $+ 0 + 0$ $+0+0$

$:.(3x^3-5x^2+10x+4)/(3x+1)=x^2-2x+4$

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How do you divide $\frac{3 x^{3} - 5 x^{2} + 10 x + 4}{3 x + 1}$ $( 3x^3 - 5x^2 + 10x +4 )/(3x+1)$ ?

1 Answer

Explanation:

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How do you divide ( 3x^3 - 5x^2 + 10x +4 )/(3x+1)3x3−5x2+10x+43x+1( 3x^3 - 5x^2 + 10x +4 )/(3x+1)?

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Explanation:

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How do you divide $\frac{3 x^{3} - 5 x^{2} + 10 x + 4}{3 x + 1}$ $( 3x^3 - 5x^2 + 10x +4 )/(3x+1)$ ?