How do you divide (4x^3 - 2x^2 + x - 7) ÷ (x - 8) (4x3−2x2+x−7)÷(x−8)?

1 Answer
Ernest Z.
Jul 1, 2015

(4x^3 -2x^2 +x -7)/(x-8) = 4x^2 +30x +241 + 1921/(x-8)4x3−2x2+x−7x−8=4x2+30x+241+1921x−8

Explanation:

You use the process of long division.

enter image source here

So,

(4x^3 -2x^2 +x -7)/(x-8) = 4x^2 +30x +241 + 1921/(x-8)4x3−2x2+x−7x−8=4x2+30x+241+1921x−8

Check:

(x-8)(4x^2 +30x +241 + 1921/(x-8))= (x-8)(4x^2+30x+241) +1921(x−8)(4x2+30x+241+1921x−8)=(x−8)(4x2+30x+241)+1921

= 4x^3 + 30x^2 + 241x -32x^2 – 240x -1928 +1921 = 4x^3 -2x^2 +x -7

Related questions
See all questions in Long Division of Polynomials
Impact of this question
1766 views around the world
You can reuse this answer
Creative Commons License