How do you divide 6x^4+x^3+1 div 2x^2-2? Precalculus Real Zeros of Polynomials Long Division of Polynomials 1 Answer Johnson Z. Dec 16, 2015 ((x^2-x+1)(6x+1))/(2(x-1)) Explanation: (6x^4+x^3+1)/(2x^2-2) =(x^3(6x+1)+1)/(2(x^2-1)) =((x^3+1)(6x+1))/(2(x+1)(x-1)) =((x+1)(x^2-x+1)(6x+1))/(2(x+1)(x-1)) =(color(red)cancelcolor(black)((x+1))(x^2-x+1)(6x+1))/(2color(red)cancelcolor(black)((x+1))(x-1)) =((x^2-x+1)(6x+1))/(2(x-1)) Answer link Related questions What is long division of polynomials? How do I find a quotient using long division of polynomials? What are some examples of long division with polynomials? How do I divide polynomials by using long division? How do I use long division to simplify (2x^3+4x^2-5)/(x+3)? How do I use long division to simplify (x^3-4x^2+2x+5)/(x-2)? How do I use long division to simplify (2x^3-4x+7x^2+7)/(x^2+2x-1)? How do I use long division to simplify (4x^3-2x^2-3)/(2x^2-1)? How do I use long division to simplify (3x^3+4x+11)/(x^2-3x+2)? How do I use long division to simplify (12x^3-11x^2+9x+18)/(4x+3)? See all questions in Long Division of Polynomials Impact of this question 1342 views around the world You can reuse this answer Creative Commons License