How do you divide (9x^3-19x^2-28x+12)div(x-3)(9x319x228x+12)÷(x3) using synthetic division?

1 Answer
May 21, 2017

The remainder is =0=0 and the quotient is =9x^2+8x-4=9x2+8x4

Explanation:

Let's perform the synthetic division

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color(white)(aaaaaaaaaaaa)aaaaaaaaaaaa_________

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color(white)(aaaaaaaaaaaa)aaaaaaaaaaaa________

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(9x^3-19x^2-28x+12)/(x-3)=(9x^2+8x-4)9x319x228x+12x3=(9x2+8x4)

The remainder is =0=0 and the quotient is =9x^2+8x-4=9x2+8x4