How do you divide #-d^3 + 7d^2 - 11d - 3# by #d+3#?
1 Answer
This can't be done exactly. I didn't work it out below, but if remainders are accepted, then the answer is -d^2 + 10d - 41 with a remainder of 120.
Explanation:
To do this, the expression needs to be able to be factored into something and (d+3).
Honestly, with polynomials of great length like this one, it's best to play around with the equation and see what you can get. Let's try to make that
We can multiply (d+3) by
Now, let's get the next term to be what we want it to be. It should be
Last step - make the 3rd term right and see if the last term automatically matches up. If it doesn't then this polynomial can't be divided evenly.
Whoa... that last term isn't right. That means this polynomial isn't divisible by (d+3). You can check this with an online polynomial divider or factorer. You'll find that this gives a remainder and the polynomial doesn't have (d+3) as a factor.