How do you divide $\frac{x^{2} + 2 x - 5}{x}$ $\frac{x^2+2x-5}{x}$ ?

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How do you divide $\frac{x^{2} + 2 x - 5}{x}$ $\frac{x^2+2x-5}{x}$ ?

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Answer 1 · 2018-05-22T06:34:44

$x + 2 - \frac{5}{x}$ $x+2-5/x$

Explanation:

$divide each term on the numerator by x$ $"divide each term on the numerator by "x$

$= \frac{x^{2}}{x} + \frac{2 x}{x} - \frac{5}{x} = x + 2 - \frac{5}{x}$ $=x^2/x+(2x)/x-5/x=x+2-5/x$

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How do you divide $\frac{x^{2} + 2 x - 5}{x}$ $\frac{x^2+2x-5}{x}$ ?

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How do you divide x2+2x−5x\frac{x^2+2x-5}{x}?

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How do you divide $\frac{x^{2} + 2 x - 5}{x}$ $\frac{x^2+2x-5}{x}$ ?