How do you divide #q^2-10q+24# by #q-4#?

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Answer 1 · 2015-05-16T20:22:54

In this case, one possible answer is by factoring your quadratic function.

In order to find its factors, you must find its roots, which are #q_1=4# and #q_2=6#.

Rewriting these roots, we get

#q_1-4=0# and #q_2-6=0#, which are now our factors:

#(q-4)(q-6)#

Now, let's just recompose your division:

#(cancel((q-4))(q-6))/cancel((q-4))#

The answer of this division is #q-6#.