How do you divide $q^2-10q+24$ by $q-4$ ?

Question

1441 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-16T20:22:54

In this case, one possible answer is by factoring your quadratic function.

In order to find its factors, you must find its roots, which are $q_1=4$ and $q_2=6$ .

Rewriting these roots, we get

$q_1-4=0$ and $q_2-6=0$ , which are now our factors:

$(q-4)(q-6)$

Now, let's just recompose your division:

$(cancel((q-4))(q-6))/cancel((q-4))$

The answer of this division is $q-6$ .

How do you divide q^2-10q+24q^2-10q+24 by q-4q-4?