How do you divide $x^{2} + 2 x^{4} - 3 x^{3} + x - 2$ $x^2 +2x^4 - 3x^3 + x - 2$ by $x^{2} - 3 x + 2$ $x^2 - 3x +2$ ?

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Answer 1 · 2016-01-15T10:00:25

See Trigonometric long division for a good explanation.

The result is $2 x^{2} + 3 x + 6$ $2x^2 +3x +6$ with remainder $13 x - 14$ $13x - 14$

See Trigonometric long division for a good explanation.

Long division

The result is $2 x^{2} + 3 x + 6$ $2x^2 +3x +6$ with remainder $13 x - 14$ $13x - 14$

How do you divide x^2 +2x^4 - 3x^3 + x - 2x2+2x4−3x3+x−2x^2 +2x^4 - 3x^3 + x - 2 by x^2 - 3x +2x2−3x+2x^2 - 3x +2?