How do you divide $\frac{x^{2} - 7 x + 12}{x - 5}$ $(x^2-7x+12)/(x-5)$ ?

Question

2221 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-29T18:53:59

$(x^2-7x+12)/(x-5) = x – 2 + 2/(x-5)$

You use the process of long division.

enter image source here

So,

$(x^2-7x+12)/(x-5) = x – 2 + 2/(x-5)$

Check:

$(x-5)(x-2+2/(x-5)) = (x-5)(x-2) + 2 = x^2 -7x +10 + 2 = x^2 -7x +12$

How do you divide (x^2-7x+12)/(x-5)x2−7x+12x−5(x^2-7x+12)/(x-5)?