How do you divide $(x^{2} - 9 x - 10) \div (x + 1)$ $(x ^ { 2} - 9x - 10) \div ( x + 1)$ ?

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How do you divide $(x^{2} - 9 x - 10) \div (x + 1)$ $(x ^ { 2} - 9x - 10) \div ( x + 1)$ ?

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Answer 1 · 2017-07-05T12:37:11

$x - 10$ $x-10$

Explanation:

$factorise the numerator and cancel common factor$ $"factorise the numerator and cancel common factor"$

$rArr((x-10)cancel((x+1)))/cancel((x+1))$

$=x-10larr" quotient"$

Answer 2 · 2017-07-05T12:43:14

$color(magenta)(x-10$

Explanation:

$(x^2-9x-10-:(x+1)$

$" "x^2-9x-10$
$color(magenta)(x)(x+1) ->ul(x^2+xlarr" Subtract")$
$" "0-10x-10$
$color(magenta)(-10)(x+1)-> ""ul(-10x-10larr" Subtract")$
$" "color(magenta)(0-0 larr" Remainder")$
$color(magenta)( x-10)$

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How do you divide $(x^{2} - 9 x - 10) \div (x + 1)$ $(x ^ { 2} - 9x - 10) \div ( x + 1)$ ?

2 Answers

Explanation:

Explanation:

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How do you divide (x ^ { 2} - 9x - 10) \div ( x + 1)(x2−9x−10)÷(x+1)(x ^ { 2} - 9x - 10) \div ( x + 1)?

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Explanation:

Explanation:

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How do you divide $(x^{2} - 9 x - 10) \div (x + 1)$ $(x ^ { 2} - 9x - 10) \div ( x + 1)$ ?