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How do you divide $\frac{x^{3} - 1}{x - 1}$ $(x^3-1) / (x-1)$ ?

1 Answer

Apr 22, 2018

$x^{2} + x + 1$ $x^2+x+1$

Explanation:

$\frac{x^{3} - 1}{x - 1}$ $(x^3-1)/(x-1)$

= $\frac{(x - 1) (x^{2} + x + 1)}{x - 1}$ $((x-1)(x^2+x+1))/(x-1)$

= $x^{2} + x + 1$ $x^2+x+1$

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