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How do you divide $x^{3} - 13 x - 18$ $x^3-13x-18$ by $x - 4$ $x-4$ ?

1 Answer

Jun 30, 2015

Using synthetic division;
$(x^{3} - 13 x - 18) \div (x - 4) = (x^{2} + 4 x + 3) R (- 6)$ $(x^3-13x-18) div (x-4) = (x^2+4x+3) R(-6)$

Explanation:

Synthetic division of polynomials is performed in a manner similar to long division.
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