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How do you divide $(x^3 - 2x - 3)/( x^2 - x - 6)$ ?

1 Answer

Apr 22, 2016

I tried long division to get:
$(x^3-2x-3)/(x^2-x-6)=(x^2-x-6)(x+1)+(5x+3)$

Explanation:

Have a look:
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