How do you divide $(x^3 + 3x^2 - 16x + 12 )/(x - 2)$ ?

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How do you divide $(x^3 + 3x^2 - 16x + 12 )/(x - 2)$ ?

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Answer 1 · 2017-02-17T16:30:37

$(x^3+3x^2-16x+12) / (x-2) = x^2+5x-6$

Explanation:

$color(white)(..............)ulcolor(white)(........)ul(x^2+5x-6)$
$color(white)(aa)x-2$ $|$ $x^3+3x^2-16x+12$
$color(white)(..............)ul(x^3-2x^2)$
$color(white)(........................)5x^2-16x$
$color(white)(........................)ul(5x^2-10x)$
$color(white)(..............................)-6x+12$
$color(white)(...............................)ul(-6x+12)$

$(x^3+3x^2-16x+12) / (x-2) = x^2+5x-6$

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How do you divide $(x^3 + 3x^2 - 16x + 12 )/(x - 2)$ ?

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How do you divide (x^3 + 3x^2 - 16x + 12 )/(x - 2)(x^3 + 3x^2 - 16x + 12 )/(x - 2)?

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How do you divide $(x^3 + 3x^2 - 16x + 12 )/(x - 2)$ ?