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How do you divide $(x^{3} + 5 x^{2} - 2) \div (x + 4)$ $(x^3+5x^2-2)div(x+4)$ using long division?

1 Answer

Aug 11, 2016

I found: $(x^{2} + x - 4)$ $(x^2+x-4)$ and $14$ $14$ as remainder.

Explanation:

Have a look:
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I introduced the $0 x$ $0x$ into the original to simplify the operation.

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