How do you divide (x3+6x230x+102)÷(x+10) using synthetic division?

1 Answer
Oct 23, 2016

The result x3+6x230x+102x+10=(x24x+10)+2x+10

Explanation:

Let's do the division
x3+6x230x+102aaaaax+10
x3+10x2aaaaaaaaaaaaaaax24x+10
04x230x
aa4x240x
aaaaa0+10x+102
aaaaaaaaa10x+100
aaaaaaaaaaa0+2

The remainder =2

so the result is x3+6x230x+102x+10=(x24x+10)+2x+10