How do you divide $(x^{3} + 6 x^{2} - 4 x + 3) \div (x + 2)$ $(x^3+6x^2-4x+3)div(x+2)$ ?

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How do you divide $(x^{3} + 6 x^{2} - 4 x + 3) \div (x + 2)$ $(x^3+6x^2-4x+3)div(x+2)$ ?

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Answer 1 · 2017-02-21T15:27:30

The remainder is $= 27$ $=27$ and the quotient is $x^{2} + 4 x - 12$ $x^2+4x-12$

Explanation:

We perform the synthetic division

$a a a a$ $color(white)(aaaa)$ $- 2$ $-2$ $a a a a$ $color(white)(aaaa)$ $∣$ $|$ $a a a a$ $color(white)(aaaa)$ $1$ $1$ $a a a a$ $color(white)(aaaa)$ $6$ $6$ $a a a a a$ $color(white)(aaaaa)$ $- 4$ $-4$ $a a a$ $color(white)(aaa)$ $3$ $3$

$a a a a a a$ $color(white)(aaaaaa)$ $a a a a a$ $color(white)(aaaaa)$ $∣$ $|$ $a a a a a$ $color(white)(aaaaa)$ $a a$ $color(white)(aa)$ $- 2$ $-2$ $a a a a$ $color(white)(aaaa)$ $- 8$ $-8$ $a a a a$ $color(white)(aaaa)$ $24$ $24$

$a a a a a a a a a a$ $color(white)(aaaaaaaaaa)$ ------------------------------------------------------------

$a a a a$ $color(white)(aaaa)$ $a a a a a a$ $color(white)(aaaaaa)$ $a a a a a a$ $color(white)(aaaaaa)$ $1$ $1$ $a a a a$ $color(white)(aaaa)$ $4$ $4$ $a a a a$ $color(white)(aaaa)$ $- 12$ $-12$ $a a a a$ $color(white)(aaaa)$ $27$ $color(red)(27)$

The remainder is $= 27$ $=27$

The quotient is $= x^{2} + 4 x - 12$ $=x^2+4x-12$

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How do you divide $(x^{3} + 6 x^{2} - 4 x + 3) \div (x + 2)$ $(x^3+6x^2-4x+3)div(x+2)$ ?

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Explanation:

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How do you divide (x^3+6x^2-4x+3)div(x+2)(x3+6x2−4x+3)÷(x+2)(x^3+6x^2-4x+3)div(x+2)?

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Explanation:

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How do you divide $(x^{3} + 6 x^{2} - 4 x + 3) \div (x + 2)$ $(x^3+6x^2-4x+3)div(x+2)$ ?