How do you divide x^3+7x^2-3x+4) div(x+2) and identify any restrictions on the variable?

1 Answer
Dec 20, 2017

x^2+5x-13+30/(x+2)to(x!=-2)

Explanation:

"one way is to use the divisor as a factor in the numerator"

"consider the numerator"

color(red)(x^2)(x+2)color(magenta)(-2x^2)+7x^2-3x+4

=color(red)(x^2)(x+2)color(red)(+5x)(x+2)color(magenta)(-10x)-3x+4

=color(red)(x^2)(x+2)color(red)(+5x)(x+2)color(red)(-13)(x+2)color(magenta)(+26)+4

=color(red)(x^2)(x+2)color(red)(+5x)(x+2)color(red)(-13)(x+2)+30

"quotient "=color(red)(x^2+5x-13)," remainder "=30

rArr(x^3+7x^2-3x+4)/(x+2)

=x^2+5x-13+30/(x+2)to(x!=-2)