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How do you divide $\frac{x^{3} + x^{2} + x + 2}{x - 4}$ $(x^3+x^2+x+2 )/(x-4)$ ?

1 Answer

Jul 20, 2018

$x^{2} + 5 x + 21 + \frac{86}{x - 4}$ $x^2 + 5x + 21 + 86/(x-4)$

Explanation:

To divide this, use long division:
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