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How do you divide $x^{4} + 2 x^{2} - x \div x^{2} + 3 x$ $x^4+2x^2-x div x^2+3x$ ?

1 Answer

Jan 22, 2016

What you have here is:

$\frac{x^{3} + 2 x - 1}{x^{2} + 3}$ $(x^3 +2x -1)/(x^2+3)$

So now dividing we find:
$(x^{2} + 3) x - x - 1$ $(x^2 +3)x-x-1$

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