How do you divide #(x^4 - 2x^3 - x + 2 )/( x^3 - 1)#?

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Answer 1 · 2016-08-28T17:12:01

#"The Quotient is" (x-2), "&, Remainder"=0#.

We see that the #"Nr."=x^4-2x^3-x+2#

#=ul(x^4-x)-ul(2x^3+2)#

#=x(x^3-1)-2(x^3-1)#

#=(x^3-1)(x-2)#

#"Therefore"=(x^4-2x^3-x+2)/(x^3-1)#

#={cancel((x^3-1))(x-2)}/(cancel(x^3-1))#

#=x-2#.