How do you divide $(x^{4} + 3 x^{3} - 8 x^{2} + 30 x - 180) \div (x + 6)$ $(x^4 + 3x^3 - 8x^2 + 30x - 180) ÷ (x + 6)$ ?

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How do you divide $(x^{4} + 3 x^{3} - 8 x^{2} + 30 x - 180) \div (x + 6)$ $(x^4 + 3x^3 - 8x^2 + 30x - 180) ÷ (x + 6)$ ?

1 Answer

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Answer 1 · 2015-09-02T11:00:07

$x^{3} - 3 x^{2} + 10 x - 30$ $x^3-3x^2+10x-30$

Explanation:

The process is commonly called "synthetic division" but it is basically just long division as demonstrated in the image below:
enter image source here

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How do you divide $(x^{4} + 3 x^{3} - 8 x^{2} + 30 x - 180) \div (x + 6)$ $(x^4 + 3x^3 - 8x^2 + 30x - 180) ÷ (x + 6)$ ?

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Explanation:

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How do you divide (x4+3x3−8x2+30x−180)÷(x+6) (x^4 + 3x^3 - 8x^2 + 30x - 180) ÷ (x + 6)?

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How do you divide $(x^{4} + 3 x^{3} - 8 x^{2} + 30 x - 180) \div (x + 6)$ $(x^4 + 3x^3 - 8x^2 + 30x - 180) ÷ (x + 6)$ ?