Question

How do you draw `45^circ` and `-45^circ` in standard position and then show that `sin(-45^circ)=-sin45^circ`?

Answer 1

I tried using a visual approach:

Explanation:

Have a look:

On the unit circle you can see that the two segments corresponding to the `sin` for the two angles and on the `sin` graph you can see the corresponding values where:
`sin(-45^@)=-sin(45^@)=-0.707`

Hope it helps.