Question

How do you draw the line with the x intercept of -4 and y intercept of -1/2?

Answer 1

See a solution process below

Explanation:

The `x`-intercept is the point on the `x`-axis where the line crosses. Therefore, the `x` value is `0`. So, we can write the `x`-intercept of `-4` as: `(0, -4)`

Likewise, the `y`-intercept is the point on the `y`-axis where the line crosses. Therefore, the `y` value is `0`. So, we can write the `y`-intercept of `-1/2` as: `(-1/2, 0)`

We can next graph the two points on the coordinate plane:

graph{(x^2+(y+4)^2-0.05)((x-0.5)^2+y^2-0.05)=0 [-15, 15, -7.5, 7.5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x^2+(y+4)^2-0.05)((x-0.5)^2+y^2-0.05)(-8x+y+4)=0 [-15, 15, -7.5, 7.5]}