How do you evaluate #2(5-(15div3))#?

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Answer 1 · 2017-07-03T06:27:03

#0#

There is only one term to be simplified.

Start with the inner brackets.

#2(5-(color(blue)(15div3)))#

#=2(5-color(blue)5)#

#=2color(red)((5-5)#

#=2color(red)((0)#

#=0#