How do you evaluate $2(5-(15div3))$ ?

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Answer 1 · 2017-07-03T06:27:03

$0$

There is only one term to be simplified.

Start with the inner brackets.

$2(5-(color(blue)(15div3)))$

$=2(5-color(blue)5)$

$=2color(red)((5-5)$

$=2color(red)((0)$

$=0$

How do you evaluate 2(5-(15div3))2(5-(15div3))?