How do you evaluate $22 \div 11 \cdot 9 - 3^{2}$ $22div11*9-3^2$ ?

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Answer 1 · 2018-03-13T20:34:29

$\frac{22}{11} \cdot 9 - 3^{2}$ $22/11*9-3^2$
$\frac{22}{11} = 2$ $22/11=2$
$2 \cdot 9 = 18$ $2*9=18$
$18 - 3^{2} = 18 - 9 = 9$ $18-3^2=18-9=9$

Answer 2 · 2018-03-13T20:45:06

Use BEDMAS.

Brackets
Exponents
Division
Multiplication
Addition
Subtraction.

Using BEDMAS we get:

Step 1: Exponents first (there are no brackets).

$22 \div 11 \times 9 - 3^{2}$ $22 div 11 times 9 - color(red)(3^2)$

$= 22 \div 11 \times 9 - 9$ $=22 div 11 times 9 - color(red)9$

Step 2: Divison next.

$22 \div 11 \times 9 - 9$ $color (red)(22 div 11) times 9 - 9$
$= 2 \times 9 - 9$ $=color (red)(2) times 9 - 9$

Step 3: Multiplication next.

$2 \times 9 - 9$ $color(red)(2 times 9) - 9$

$= 18 - 9$ $=color(red)18- 9$

Step 4: Subtraction next (there are no terms that need addition).

$18 - 9$ $color (red)18-9$

$= 9$ $=color(red)9$

How do you evaluate 22÷11⋅9−3222div11*9-3^2?