Question

How do you evaluate `3 * (-2) +6 -(-2) - 5`?

Answer 1

`-3`

Explanation:

`3(-2)+6-(-2)-5=?`

PEMDAS

`-6+6-(-2)-5`

`-6+6+(2)-5`

combine

`2-5`

`2+ (-5)`

so, the answer is:
`-3`

Answer 2

`-` `3`

Explanation:

Use your order of operations.

`3` `xx`(`-` `2`)`+` `6` `-`(`-` `2`)`-` `5`

The parentheses here are only making it obvious that the numbers are negative, so let's get rid of them.

`3` `xx` `-` `2` `+` `6` `-` `-` `2` `-` `5`

Next up on the order of operations is exponents, but we don't have any, so we move to multiplication.

`3` `xx` `-` `2`

`3` `xx` `-` `2` is `-`(`3` `xx` `2`), which is `-` `6`

`-` `6` `+` `6` `-` `-` `2` `-` `5`

Since there is no more multiplication and no division is present, we move on to addition and subtraction. It's pretty easy from here.

`-` `6` `+` `6` `=` `0`

Next we've got a double negative. Whenever we subtract a negative number, we add instead.

`0` `+` `2` `-` `5`

`2` `-` `5`

`-` `3`

Well, that wasn't too hard, was it?

Answer 3

`-3`

Explanation:

Count the number of terms first.
Simplify each term separately.

`color(red)(3xx(-2))" "color(blue)(+6)" "color(green)(-(-2))" "color(purple)(-5)" "larr` there are `4` terms

`=color(red)(-6)" "color(blue)(+6)" "color(green)(+2)" "color(purple)(-5)`

`=" " 0" "+" "2" "-5" "larr (-6+6=0)`

`=-3`