How do you evaluate #(3.2 \times 10^6) \cdot (8.7 \times 10^{11})#?

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Answer 1 · 2014-11-05T18:34:35

#(3.2 times 10^6)cdot(8.7 times 10^{11})#

by rearrange factors,

#=(3.2 cdot 8.7) times (10^6 cdot 10^{11})#

by multiplying out,

#=27.84 times 10^{17}#

by moving the decimal point 1 digit to the left,

#=2.784 times 10^{18}#

I hope that this was helpful.