Question

How do you evaluate `3-(-6) + (-h) + (-4)` where `h=-7`?

Answer 1

`12`

Explanation:

`3-(-6)+(-h)+(-4)`

`:.=3+6-h-4`

`:.=9-h-4`

substitute `h=-7`

`:.=9-(-7)-4`

`:.=9+7-4`

`:.=16-4`

`:.=12`