How do you evaluate #-4p - 27= - 5( 1+ 7p ) + 9#?

Question

↳Redirected from "What is the oxidation number of copper?"

1595 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-24T21:22:10

#p=1#

Expand the bracket

#-4p-27=-5-35p+9#

Add #35p# to both sides

#31p-27=4#

Add 27 to both sides

#31p=31#

Divide both sides by 31

#p=1#