How do you evaluate #5(3+12) + 42(23-4) #?

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Answer 1 · 2015-07-07T06:04:07

Distribute the #5# and the #42#. Add and subtract from left to right.

Distribute the #5# and the #42#.

Multiply #5# times the terms in the first set of parentheses, and multiply #42# times the terms in the second set of parentheses.

#5*3+5*12+42*23-42*4# =

#15+60+966-168# =

Add and subtract from left to right.

#1041-168=873#

Answer 2 · 2015-07-07T11:18:49

Rather than distributing to remove the parentheses, you could do the parentheses first, then multiply, then add.

#5(3+12) + 42(23-4)#

# = 5(15)+42(19)#

# = 75 + 798#

# = 873#