How do you evaluate $5 (3 + 12) + 42 (23 - 4)$ $5(3+12) + 42(23-4)$ ?

Question

1902 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-07T06:04:07

Distribute the $5$ $5$ and the $42$ $42$ . Add and subtract from left to right.

Distribute the $5$ $5$ and the $42$ $42$ .

Multiply $5$ $5$ times the terms in the first set of parentheses, and multiply $42$ $42$ times the terms in the second set of parentheses.

$5 \cdot 3 + 5 \cdot 12 + 42 \cdot 23 - 42 \cdot 4$ $5*3+5*12+42*23-42*4$ =

$15 + 60 + 966 - 168$ $15+60+966-168$ =

Add and subtract from left to right.

$1041 - 168 = 873$ $1041-168=873$

Answer 2 · 2015-07-07T11:18:49

Rather than distributing to remove the parentheses, you could do the parentheses first, then multiply, then add.

$5 (3 + 12) + 42 (23 - 4)$ $5(3+12) + 42(23-4)$

$= 5 (15) + 42 (19)$ $= 5(15)+42(19)$

$= 75 + 798$ $= 75 + 798$

$= 873$ $= 873$

How do you evaluate 5(3+12)+42(23−4)5(3+12) + 42(23-4) ?