How do you evaluate $(5-w)^2+x$ if w=6, x=0.4, y=1/2, z=-3?

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Answer 1 · 2017-06-09T18:58:41

$1.4$

$"substitute the given values into the expression"$

$rArr(5color(red)(-6))^2+color(magenta)(0.4)$

$=(-1)^2+0.4$

$=1+0.4$

$=1.4$

How do you evaluate (5-w)^2+x(5-w)^2+x if w=6, x=0.4, y=1/2, z=-3?