How do you evaluate $6 \div 6 - (1 + 2 - 2)$ $6\div 6- ( 1+ 2- 2)$ ?

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How do you evaluate $6 \div 6 - (1 + 2 - 2)$ $6\div 6- ( 1+ 2- 2)$ ?

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Answer 1 · 2017-10-06T19:20:28

$0$ $0$

Explanation:

$following the order of operations as set out in PEMDAS$ $"following the order of operations as set out in PEMDAS"$

$[Parenthesis (brackets),Exponents (powers),$ $["Parenthesis (brackets),Exponents (powers"),$
$Multiplication ,Division ,Addition ,Subtraction]$ $"Multiplication ,Division ,Addition ,Subtraction"]$

$\Rightarrow 6 \div 6 - (1) \leftarrow brackets$ $rArr6-:6-(color(red)1)larrcolor(blue)" brackets"$

$= 1 - 1 \leftarrow division$ $=1-1larrcolor(blue)" division"$

$= 0$ $=0$

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How do you evaluate $6 \div 6 - (1 + 2 - 2)$ $6\div 6- ( 1+ 2- 2)$ ?

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How do you evaluate 6÷6−(1+2−2)6\div 6- ( 1+ 2- 2)?

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How do you evaluate $6 \div 6 - (1 + 2 - 2)$ $6\div 6- ( 1+ 2- 2)$ ?