How do you evaluate #68 - y^2# for y = 5? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer Alan P. Jul 8, 2015 Replace #y# with #5# in the expression and perform the arithmetic to get #color(white)("XXXX")##43# Explanation: #68-y^2# with #y=5# becomes #68 -5^2# #color(white)("XXXX")##=68 - 25# #color(white)("XXXX")##= 43# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1845 views around the world You can reuse this answer Creative Commons License