How do you evaluate $(7+3^2)/(4^2*2)$ ?

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Answer 1 · 2016-12-24T15:27:20

$1/2$

We first calculate the term with exponents:

$(7 + color(red)(3^2))/(color(blue)(4^2)*2) -> (7 + (color(red)(3*3)))/((color(blue)(4*4))*2) -> (7 + color(red)(9))/(color(blue)(16)*2)$

Next we can add the terms in the numerator:

$(7 + color(red)(9))/(color(blue)(16)*2) -> 16/(color(blue)(16)*2)$

Now, we can simplify the numerator and denominator:

$16/(color(blue)(16)*2) -> color(blue)(cancel(color(black)(16)))/(cancel(color(blue)(16))*2) -> 1/2$

How do you evaluate (7+3^2)/(4^2*2)(7+3^2)/(4^2*2)?