How do you evaluate [(7-5)^5/8]-4?

1 Answer
Jun 16, 2015

The answer is zero.

Explanation:

First, note that the parentheses mean that 7-5 should be computed first to get 7-5=2. Then raise that to the fifth power to get (7-5)^5=2^5=32 (powers come before divisions in order of operations). Then divide by 8 to get ((7-5)^2)/8=32/8=4. Finally, subtract 4 to get ((7-5)^2)/8-4=4-4=0.

The outer brackets [ ] are not technically needed in the notation.