How do you evaluate $(8+ \sqrt { 3^ { 2} + 2\cdot 3+ 1})/-4$ ?

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Answer 1 · 2018-08-04T06:53:45

$-3$

$(8 + sqrt(3^2 + 2 * 3 + 1))/-4$

$=(8 + sqrt(9 + 6 + 1))/-4$

$=(8 + sqrt(16))/-4$

$=(8+4)/-4$

$=12/-4$

$=-3$

Hope this helps!

How do you evaluate (8+ \sqrt { 3^ { 2} + 2\cdot 3+ 1})/-4(8+ \sqrt { 3^ { 2} + 2\cdot 3+ 1})/-4?