How do you evaluate #8(x-2)+3x# when x=6? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer Anthony R. Apr 16, 2017 #50# Explanation: Substitute #6# for #x# and evaluate: #8(color(red)6-2)+3(color(red)6)# #=8(4)+18# #=32+18# #=50# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1665 views around the world You can reuse this answer Creative Commons License