How do you evaluate $a (b^{x})$ $a(b^x)$ given a=-3, b=5, x=2?

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Answer 1 · 2018-04-18T21:30:49

$- 75$ $-75$

$a (b^{x})$ $a(b^x)$ is the same as $a \cdot b^{x}$ $a * b^x$ .

here, $a = - 3$ $a = -3$

$b = 5$ $b = 5$ and $x = 2$ $x = 2$ , so $b^{x} = 5^{2}$ $b^x = 5^2$

$5^{2} = 25$ $5^2 = 25$

$- 3 \cdot 5^{2} = - 3 \cdot 25$ $-3 * 5^2 = -3 * 25$

$= - 75$ $= -75$

How do you evaluate a(bx)a(b^x) given a=-3, b=5, x=2?