How do you evaluate #abs(-4)/2timesabs(-1times8)#?

1 Answer
Dec 4, 2016

The answer is #16#.

Explanation:

Taking the absolute value of a number means finding its distance from 0.

First, we simplify within the absolute value bars as much as we can:

#abs(-4)/2timesabs(-1times8)#

#=abs(-4)/2timesabs(-8)#

To solve this, we need to simplify #abs(-4)# and #abs(-8)#. Since it would take 4 steps to walk from #-4# to #0#, we have

#abs(-4)=4#.

Similarly, since the distance between #-8# and #0# is 8, we have

#abs(-8)=8#.

This allows us to simplify from where we left off:

#abs(-4)/2timesabs(-8)#

#=4/2times8#

#=2times8#

#=16#

Bonus:

The clever shortcut for simplifying absolute values is to simply take the positive value of the number inside. In other words, for all positive numbers #n#,

#abs(n)=abs(-n)=n#.

eg: #abs(42)=abs(-42)=42#, because both #42# and #-42# are forty-two steps from 0.