Question

How do you evaluate `abs(x-y)+y-1` when x=-3, y=-6?

Answer 1

`|x-y|+y-1=-4`, when `x=-3` and `y=-6`

Explanation:

Value of `|x-y|+y-1`, when `x=-3` and `y=-6` can be obtained by substituting these values.

`|x-y|+y-1`

= `|(-3)-(-6)|+(-6)-1`

= `|-3+6|+(-6)-1`

= `|3|-6-1`

= `3-6-1=3-7=-4`