How do you evaluate $abs(x-y)+y-1$ when x=-3, y=-6?

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Answer 1 · 2016-11-23T05:17:03

$|x-y|+y-1=-4$ , when $x=-3$ and $y=-6$

Value of $|x-y|+y-1$ , when $x=-3$ and $y=-6$ can be obtained by substituting these values.

$|x-y|+y-1$

= $|(-3)-(-6)|+(-6)-1$

= $|-3+6|+(-6)-1$

= $|3|-6-1$

= $3-6-1=3-7=-4$

How do you evaluate abs(x-y)+y-1abs(x-y)+y-1 when x=-3, y=-6?