Question

How do you evaluate `arc cos(sin((pi/3))`?

Answer 1

`arccos(sin(pi/3))=arccos(sqrt3/2)=pi/6`

Explanation:

The restriction for the range of arccos x is `[0,pi]` and since `pi/3` is in the restriction we find the ratio for `sin (pi/3)` which is `sqrt3/2`. Then `arccos(sqrt3/2)=pi/6`