How do you evaluate $arccos (\frac{\sqrt{2}}{2})$ $arccos (sqrt2/2)$ ?

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Answer 1 · 2015-07-14T04:57:37

Evaluate $arccos (\frac{\sqrt{2}}{2})$ $arccos ((sqrt2)/2)$

$cos x = \frac{\sqrt{2}}{2}$ $cos x = (sqrt2)/2$ --> Arc $x = \pm \frac{π}{4}$ $x = +- pi/4$ or $\pm 45$ $+-45$ deg

How do you evaluate arccos(√22)arccos (sqrt2/2)?