How do you evaluate $Arctan(1/2)+arctan(1/3)$ ?

Question

2944 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-12T16:34:31

$arc tan 1$ =pi/4, the principal against the principal values. The general value is $npi+pi/4, n=0, +-1, +-2. +-3,...$

Use tan ( a + b )=( tan a + tan b )/( 1 - tan a tan b).

Here, the tangent of the sum of the angles #=(1/2+1/3)/(1-(1/2)(1/3))=1.

Answer is the inverse $tan^(-1) 1$ . Now, see the answer. again.

How do you evaluate Arctan(1/2)+arctan(1/3)Arctan(1/2)+arctan(1/3)?