How do you evaluate $arctan (- (\sqrt{3}))$ $arctan ( - (sqrt 3))$ ?

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Answer 1 · 2016-07-20T11:52:50

$arctan (- \sqrt{3}) = - \frac{π}{3}$ $arctan(-sqrt3)=-pi/3$ .

$arctanx=theta, x in RR iff tantheta=x, theta in (-pi/2,pi/2)$

We have, $tan(-pi/3)=-tan(pi/3)=-sqrt3, where, -pi/3 in (-pi/2,pi/2)$

$:. arctan(-sqrt3)=-pi/3$ .

How do you evaluate arctan ( - (sqrt 3))arctan(−(√3))arctan ( - (sqrt 3))?