Question

How do you evaluate `arctan(-sqrt(3)/3)`?

Answer 1

`-\pi/6`

Explanation:

Remember: `-\pi/2\le \tan^{-1}\le \pi/2`

Given that

`\tan^{-1}(-\sqrt3/3)`

`=\tan^{-1}(-1/\sqrt3)`

`=-\tan^{-1}(1/\sqrt3)`

`=-\pi/6`