How do you evaluate ${cos}^{- 1} (\frac{1}{2})$ $cos^-1(1/2)$ ?

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Answer 1 · 2016-10-29T18:37:50

${cos}^{- 1} (\frac{1}{2}) = \frac{π}{3}$ $cos^(-1)(1/2)=pi/3$

As $cos (\frac{π}{3}) = \frac{1}{2}$ $cos(pi/3)=1/2$ ,

${cos}^{- 1} (\frac{1}{2}) = \frac{π}{3}$ $cos^(-1)(1/2)=pi/3$

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