How do you evaluate ${cos}^{- 1} (cos (\frac{11 π}{6}))$ $cos^-1(cos((11pi)/6))$ ?

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Answer 1 · 2016-07-09T17:01:32

$\frac{11 π}{6}$ $(11pi)/6$

Use $[{cos}^{- 1} cos]$ $[cos^(-1)cos]$ is unit operator that returns the operand as the

result.

Here the operand is $\frac{11 π}{6}$ $(11pi)/6$ , and so, the answer is $\frac{11 π}{6}$ $(11pi)/6$ .

How do you evaluate cos−1(cos(11π6))cos^-1(cos((11pi)/6))?